A) \[{{10}^{3}}N{{m}^{2~}}{{C}^{-1}}\]
B) \[{{10}^{3}}C{{N}^{-1}}{{m}^{-2}}\]
C) \[6.32\times {{10}^{3}}N{{m}^{2}}{{C}^{-1}}\]
D) \[6.32\times 103\text{ }C{{N}^{-1}}{{m}^{-2}}\]
Correct Answer: A
Solution :
Electric flux \[=\frac{q}{{{\varepsilon }_{0}}}\] \[=\frac{(-14+78.85-56)\times {{10}^{-9}}}{8.85\times {{10}^{-12}}}\] \[=\frac{8.85\times {{10}^{-9}}}{8.85\times {{10}^{-12}}}=1000N{{m}^{2}}{{C}^{-1}}\]
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