A) 2 r
B) 4 r
C) r/4
D) r/2
Correct Answer: B
Solution :
Radius of path of electron \[r=\frac{m\upsilon }{Bq}\] m and q remain unchanged. So, \[\frac{{{r}_{1}}}{{{r}_{2}}}=\frac{{{\upsilon }_{1}}}{{{\upsilon }_{2}}}.\frac{{{B}_{2}}}{{{B}_{1}}}\] \[=\frac{\upsilon }{2\upsilon }.\frac{B/2}{B}=\frac{1}{4}\Rightarrow {{r}_{2}}=4r\]You need to login to perform this action.
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