CET Karnataka Medical CET - Karnataka Medical Solved Paper-2005

  • question_answer
    Mean life of a radioactive sample is 100 seconds. Then its half-life (in minutes) is:

    A)  0.693

    B)  1

    C)  \[{{10}^{-4}}\]

    D)  1.155

    Correct Answer: D

    Solution :

    Half life \[T/2=\frac{T}{1.44}=\frac{100}{1.44}\sec \] \[=69.44\sec \] \[=\frac{69.44}{60}\simeq 1.155\min \]


You need to login to perform this action.
You will be redirected in 3 sec spinner