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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2005

  • question_answer
    15 moles of \[{{H}_{2}}\]and 5.2 moles of \[{{I}_{2}}\] are mixed and allowed to attain equilibrium at   \[{{500}^{o}}C\].   At   equilibrium,   the concentration of \[HI\] is found to be 10 moles. The equilibrium constant for the formation of \[HI\] is:

    A)  \[50\]             

    B)  \[15\]

    C)  \[100\]            

    D)  \[25\]

    Correct Answer: A

    Solution :

    \[\underset{(15-5)}{\mathop{\underset{15}{\mathop{{{H}_{2}}}}\,}}\,+\underset{(5.2-5)}{\mathop{\underset{5.2}{\mathop{{{I}_{2}}}}\,}}\,\underset{10}{\mathop{\underset{0}{\mathop{2HI}}\,}}\,\] Equilibrium constant \[({{K}_{c}})=\frac{{{(HI)}^{2}}}{[{{H}_{2}}][{{I}_{2}}]}=\frac{10\times 10}{10\times 0.2}=50\]


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