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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2005

  • question_answer
    For the reaction \[{{N}_{2}}_{(g)}+{{O}_{2}}_{(g)}2N{{O}_{(g)}}\]the value of \[{{K}_{c}}\] at \[{{800}^{o}}C\]is 0.1. When the equilibrium concentration of both the reactants is \[0.5mol\], what is the value of \[{{K}_{p}}\] at the same temperature?

    A)  \[0.5\]              

    B)  \[0.1\]

    C)  \[0.01\]            

    D)  \[0.025\]

    Correct Answer: B

    Solution :

    \[{{N}_{2}}(g)+{{O}_{2}}(g)2NO(g)\] \[{{K}_{c}}=0.1,\,\,{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta n}}\] \[\Delta n\] = Number of gaseous product - Number of gaseous reactants \[\Delta n=2-2=0\] \[\Delta n=0\] \[\therefore \] \[{{K}_{p}}={{K}_{c}}=0.1\]


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