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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2005

  • question_answer
    The hydrogen electrode is dipped in a solution of pH 3 at\[{{25}^{o}}C\]. The potential would be (the value of \[2.303\text{ }RT/F\]is \[0.059V\]):

    A)  \[0.177V\]        

    B)  \[0.087V\]

    C)  \[0.059V\]

    D)  \[-0.177V\]

    Correct Answer: D

    Solution :

    \[pH=3,[{{H}^{+}}]={{10}^{-3}}\] \[E=E_{red}^{o}+0.059\log (ion)\] \[E=0+0.059\,\log \,({{10}^{-3}})\] \[E=+0.059\,(-3)=-0.177V\]


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