A) \[2g\]
B) \[600mg\]
C) \[1g\]
D) \[1.5g\]
Correct Answer: A
Solution :
\[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}},\,\,\,n=\frac{40}{10}=4\] \[\frac{125}{1000}=N{{\left( \frac{1}{2} \right)}^{4}},{{N}_{0}}=\frac{125\times {{2}^{4}}}{1000}=2g\]
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