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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2006

  • question_answer
     For a reaction \[A+B\xrightarrow{{}}C+D\] if the concentration of A is doubled without altering the concentration of B, the rate gas doubled. If the concentration of B is increased by nine times without altering the concentration of A, the rate gets tripled. The order of the reaction is:

    A)  \[2\]

    B)  \[1\]

    C)  \[3/2\]

    D)  \[4/3\]

    Correct Answer: C

    Solution :

    \[A+B\xrightarrow{{}}C+D\] Rate \[(r)=k{{[A]}^{a}}\,{{[B]}^{b}}\]           ??.(i) \[2r=k{{[2A]}^{a}}\,{{[B]}^{b}}\]          ???(ii) \[3r=k{{[A]}^{a}}\,{{[9B]}^{b}}\]         ??(iii) Dividing Eq. (ii) by Eq. (i) \[2={{2}^{a}}\] or  \[a=1\] Dividing Eq. (iii) by Eq. (i) \[3={{9}^{b}}\] or \[3={{3}^{2b}}\] or \[2b=1\] or \[b=\frac{1}{2}\] So, order of reaction \[=1+\frac{1}{2}=\frac{3}{2}\] \[\Delta {{T}_{b}}=i.\,\,{{k}_{b}}.M\]


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