A) 12 molecules of ATP and 18 molecules of \[NADP{{H}_{2}}\]
B) 6 molecules of ATP and 12 molecules of \[NADP{{H}_{2}}\]
C) 18 molecules of ATP and 12 molecules of \[NADP{{H}_{2}}\]
D) 12 molecules each of ATP and \[NADP{{H}_{3}}\]
Correct Answer: D
Solution :
Assimilation and reduction of \[C{{O}_{2}}\] takes place during calvin cycle. This cycle takes in only one carbon (As \[C{{O}_{2}}\]) at a rime so it takes six turns to produce a hexose or glucose molecule (6 cabon). In calvin cycle for formation of one mole of hexose sugar (glucose) 18 ATP and 12 \[NADP{{H}_{2}}\] are used. The assimilatory power (\[NADP{{H}_{2}}\] and ATP) are generated in light reaction of photosynthesis.
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