CET Karnataka Medical CET - Karnataka Medical Solved Paper-2006

  • question_answer
    A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length. A current of 5 A falls through it. The magnetic field at the axis inside the solenoid is:

    A)  \[2\pi \times {{10}^{-3}}T\]

    B)  \[2~\pi \times {{10}^{-5}}T\]

    C)  \[4\pi \times {{10}^{-2}}T\]

    D)  \[4\pi \times {{10}^{-3}}T\]

    Correct Answer: A

    Solution :

    Magnetic field at the axis inside the solenoid \[B={{\mu }_{0}}ni\] Here, n = 10 turns/cm = 1000 turns/m, i = 5A \[\therefore \] \[B=4\pi \times {{10}^{-7}}\times 1000\times 5\] \[=2\pi \times {{10}^{-3}}T.\]


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