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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2006

  • question_answer
    \[0.06mole\]of \[KN{{O}_{3}}\] solid is added to \[100c{{m}^{3}}\]of water at 298K. The enthalpy of \[KN{{O}_{3}}\]aqueous solution is \[35.8kJ\text{ m}o{{l}^{-1}}\]. After the solute is dissolved the temperature of the solution will be:

    A)  \[293K\]         

    B)  \[298K\]

    C)  \[301K\]         

    D)  \[304K\]

    Correct Answer: A

    Solution :

    We know that \[PV=nRT\] or \[PV=\frac{w}{m}RT\] or \[m=\frac{w}{v}\frac{RT}{P}\] or \[M=d\frac{RT}{P}\] \[d=1.964g/d{{m}^{3}}=1.964\times {{10}^{-3\text{ }}}g/cc.\] \[P=76cm=1\text{ }atm\] \[R=0.0812L\,\,atm\,{{K}^{-1}}mo{{l}^{-1}}\] \[=8.21cc\,atm\,{{K}^{-1}}\,mo{{l}^{-1}}\] \[T=273K\] \[m=\frac{1.964\times {{10}^{-3}}\times 82.1\times 273}{1}=44.\] The molecular weight of \[C{{O}_{2}}\] is 44. So, the gas is \[C{{O}_{2}}\].


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