A) \[NO_{2}^{-}\]
B) \[{{H}_{2}}\overset{\centerdot \centerdot }{\mathop{N}}\,C{{H}_{2}}C{{H}_{2}}\overset{\centerdot \centerdot }{\mathop{N}}\,{{H}_{2}}\]
C) \[{{H}_{2}}O\]
D) \[_{\centerdot }^{\centerdot }N{{H}_{3}}\]
Correct Answer: A
Solution :
\[NO_{2}^{-}\] can participate in linkage isomerism because it may be bonded to metal through nitrogen or through oxygen. \[\underset{\text{cobalt}\,\text{(III)}\,\text{chloride}}{\mathop{\underset{\text{Pentaamminenenitro}}{\mathop{\text{ }\!\![\!\!\text{ (N}{{\text{H}}_{\text{3}}}{{\text{)}}_{\text{5}}}\text{CoN}{{\text{O}}_{\text{2}}}\text{ }\!\!]\!\!\text{ C}{{\text{l}}_{\text{2}}}}}\,}}\,\] and \[\underset{\text{cobalt}\,\text{(III)}\,\text{chloride}}{\mathop{\underset{\text{Pentaamminenitro}}{\mathop{\text{ }\!\![\!\!\text{ (N}{{\text{H}}_{\text{3}}}\text{)CoONO }\!\!]\!\!\text{ C}{{\text{l}}_{\text{2}}}}}\,}}\,\]
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