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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2006

  • question_answer
    The radii of \[N{{a}^{+}}\] and \[C{{l}^{-}}\] ions are 95 pm and 181 pm respectively. The edge length of \[NaCl\]unit cell is:

    A)  \[276pm\]      

    B)  \[138pm\]

    C)  \[552pm\]     

    D)  \[415pm\]

    Correct Answer: C

    Solution :

    \[NaCl\] has fee structure. In fee lattice \[{{r}^{+}}+{{r}^{-}}=\frac{a}{2}\] where a = edge length \[{{r}^{+}}=95pm\] \[{{r}^{-}}=181pm\] Edge length \[=2{{r}^{+}}+2{{r}^{-}}\] \[=(2\times 95+2\times 181)pm\] \[=190+362=552pm\]


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