A) 0.25 H
B) 0.4 H
C) 2.5 H
D) 4 H
Correct Answer: C
Solution :
Induced emf, \[e=\frac{-LdI}{dt}\] \[\therefore \] \[100=\frac{-L[0-4]}{0.1}\] \[\Rightarrow \] \[L=\frac{100\times 0.1}{4}\]\[=2.5H\]
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