A) \[si{{n}^{-1}}\left( 0.01 \right)\]
B) \[si{{n}^{-1}}\left( 0.0001 \right)\]
C) \[si{{n}^{-1}}\left( 0.001 \right)~\]
D) \[si{{n}^{-1}}\left( 0.1 \right)\]
Correct Answer: C
Solution :
In Youngs double slit experiment half angular width is given by \[\sin \theta =\frac{\lambda }{d}\] \[=\frac{589\times {{10}^{-9}}}{0.589\times {{10}^{-3}}}={{10}^{-3}}\] \[\Rightarrow \] \[\theta ={{\sin }^{-1}}(0.001)\]
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