CET Karnataka Medical CET - Karnataka Medical Solved Paper-2007

  • question_answer
    Two identical charges repel each other with a force equal to 10 mg wt when they are 0.6 m a part in air\[\left( g=10m{{s}^{-2}} \right)\]. The value of each charge is

    A) \[2\text{ }mC\]

    B)  \[2\times {{10}^{-7}}C\]

    C) \[2\text{ }nC\]

    D)  \[2\mu C\]

    Correct Answer: D

    Solution :

    Coulomb force is given by \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] \[\therefore \]\[(10\times {{10}^{-3}})\times 10=\frac{(9\times {{10}^{9}})\times {{q}^{2}}}{{{(0.6)}^{2}}}\] \[[\because {{q}_{1}}={{q}_{2}}=q]\] or \[{{q}^{2}}=\frac{{{10}^{-1}}\times 0.36}{9\times {{10}^{9}}}\] \[=4\times {{10}^{-12}}\]


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