| A | B | Y |
| 0 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
A) NOR
B) AND
C) XOR
D) NAND
Correct Answer: D
Solution :
The output Y is a combination of AND + NOT gate. Hence, the truth table is for NAND gate.
You need to login to perform this action.
You will be redirected in
3 sec
