A) kinetic energy of \[{{O}_{2}}>\] kinetic energy of \[S{{O}_{2}}\]
B) kinetic energy of \[{{O}_{2}}<\] kinetic energy of \[S{{O}_{2}}\]
C) kinetic energy of both are equal
D) None of the above
Correct Answer: B
Solution :
\[KE=\frac{3}{2}RT\] \[KE\propto T\] \[\frac{K{{E}_{{{O}_{2}}}}}{K{{E}_{S{{O}_{2}}}}}=\frac{{{T}_{{{O}_{2}}}}}{{{T}_{S{{O}_{2}}}}}=\frac{273}{546}=\frac{1}{2}\] \[K{{E}_{S{{O}_{2}}}}=2K{{E}_{{{O}_{2}}}}\] \[\therefore \] \[K{{E}_{S{{O}_{2}}}}>2K{{E}_{{{O}_{2}}}}\]
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