A) 9 : 1
B) 1 : 9
C) 3 : 1
D) 1 : 3
Correct Answer: A
Solution :
\[v=\frac{1}{2l}\sqrt{\frac{T}{m}}\]\[\Rightarrow \]\[v\propto \frac{\sqrt{T}}{l}\] \[\frac{{{T}_{2}}}{{{T}_{1}}}={{\left[ \frac{{{v}_{2}}}{{{v}_{1}}} \right]}^{2}}{{\left[ \frac{{{l}_{2}}}{{{l}_{1}}} \right]}^{2}}={{\left[ \frac{300}{200} \right]}^{2}}{{\left[ \frac{2l}{l} \right]}^{2}}=\frac{9}{1}\]You need to login to perform this action.
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