CET Karnataka Medical CET - Karnataka Medical Solved Paper-2008

  • question_answer
    A certain current on passing through a galvanometer produces a deflection of 100 divisions. When a shunt of one ohm is connected, the deflection reduces to 1 division. The galvanometer resistance is

    A)  100\[\Omega \]         

    B)  99\[\Omega \]

    C)  10\[\Omega \]

    D)  9.9\[\Omega \]

    Correct Answer: B

    Solution :

    Shunt is connected to the galvanometer is \[{{i}_{g}}=\frac{i\,S}{S+G}\] \[1=\frac{100\times 1}{(S+G)}\] \[\Rightarrow \] \[G=99\Omega \]


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