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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2008

  • question_answer
    With what velocity should an observer approach a stationary sound source, so that the apparent frequency of sound should appear double the actual frequency? (v is velocity of sound).

    A)  \[\frac{v}{2}\]              

    B)  \[3v\]

    C)  \[2v\]

    D)  \[v\]

    Correct Answer: D

    Solution :

    By using      \[v=v\left[ \frac{v-{{v}_{0}}}{v-{{v}_{s}}} \right]\] \[2v=v\left[ \frac{v-{{v}_{0}}}{v-0} \right]\] \[\Rightarrow \] \[{{v}_{0}}=-v.\] Negative sign indicates that observer is moving opposite to the direction of velocity of sound.


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