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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2008

  • question_answer
    A string vibrates with a frequency of 200 Hz. When its length is doubled and tension is altered, it begins to vibrate with a frequency of 300 Hz. The ratio of the new tension to the original tension is

    A)  9 : 1           

    B)  1 : 9

    C)  3 : 1            

    D)  1 : 3

    Correct Answer: A

    Solution :

    \[v=\frac{1}{2l}\sqrt{\frac{T}{m}}\]\[\Rightarrow \]\[v\propto \frac{\sqrt{T}}{l}\] \[\frac{{{T}_{2}}}{{{T}_{1}}}={{\left[ \frac{{{v}_{2}}}{{{v}_{1}}} \right]}^{2}}{{\left[ \frac{{{l}_{2}}}{{{l}_{1}}} \right]}^{2}}={{\left[ \frac{300}{200} \right]}^{2}}{{\left[ \frac{2l}{l} \right]}^{2}}=\frac{9}{1}\]


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