A) 1 : 4
B) 1 : 2
C) 1 : 3
D) 1 : 6
Correct Answer: A
Solution :
Let initial activity of both substances are same. \[\therefore \] \[R={{R}_{0}}{{\left( \frac{1}{2} \right)}^{n}}={{R}_{0}}{{\left( \frac{1}{2} \right)}^{t/{{t}_{1}}/2}}\] \[\Rightarrow \] \[\frac{{{R}_{1}}}{{{R}_{2}}}\frac{{{\left( \frac{1}{2} \right)}^{4/1}}}{{{\left( \frac{1}{2} \right)}^{4/2}}}={{\frac{\left( \frac{1}{2} \right)}{{{\left( \frac{1}{2} \right)}^{2}}}}^{4}}={{\left( \frac{1}{2} \right)}^{2}}\] \[\Rightarrow \] \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{1}{4}\]
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