A) 32 V
B) 48 V
C) 24 V
D) 14 V
Correct Answer: B
Solution :
From the given circuit \[{{V}_{A}}-(6\times 2)-12-(9\times 2)+4-(5\times 2)={{V}_{B}}\] or \[{{V}_{A}}-12-12-18+4-10={{V}_{B}}\]\[\Rightarrow \] or \[{{V}_{A}}-{{V}_{B}}=48\]volt
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