A) \[1g\]
B) \[16g\]
C) \[1.6g\]
D) \[0.1g\]
Correct Answer: C
Solution :
Mass of one mole of methane \[(C{{H}_{4}})=16g\] Mass of 0.1 mole of methane \[16\times 0.1g=1.6g\]
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