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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2009

  • question_answer
    \[5moles\]of \[S{{O}_{2}}\] and 5 moles of \[{{O}_{2}}\] are allowed to react. At equilibrium, it was found that 60% of \[S{{O}_{2}}\] is used up. If the partial pressure of the equilibrium mixture is one atmosphere, the partial pressure of \[{{O}_{2}}\] is

    A) \[0.82atm\]

    B) \[0.52atm\]

    C) \[0.21atm\]

    D) \[0.41atm\]

    Correct Answer: D

    Solution :

    \[\begin{align}   & Initial \\  & At\,equilibriu\underset{=2}{\mathop{m\underset{(5-3)}{\mathop{\underset{5}{\mathop{2S{{O}_{2}}(g)}}\,}}\,}}\,+\underset{=3.5}{\mathop{\underset{(5-1.5)}{\mathop{\underset{5}{\mathop{{{O}_{2}}(g)}}\,}}\,}}\,\underset{3}{\mathop{\underset{0}{\mathop{2S{{O}_{3}}(g)}}\,}}\, \\ \end{align}\]\[\therefore \] \[p{{O}_{2}}=\frac{3.5\times 1}{8.5}=0.41atm\]


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