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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2009

  • question_answer
    The magnetic moment of a transition metal ion is \[\sqrt{15}\text{ }BM\]. Therefore, the number of unpaired electrons present in it, is

    A)  \[3\]              

    B)  \[4\]

    C)  \[1\]               

    D)  \[2\]

    Correct Answer: A

    Solution :

    \[\mu =\sqrt{n(n+2)}\] \[\Rightarrow \] \[\sqrt{15}=\sqrt{n(n+2)}\] \[\therefore \] \[n=3\]


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