CET Karnataka Medical CET - Karnataka Medical Solved Paper-2009

  • question_answer
    The kinetic energy of an electron gets tripled, then the de-Broglie wavelength associated with it changes by a factor

    A)  \[\frac{1}{3}\]

    B)  \[\sqrt{3}\]

    C)  \[\frac{1}{\sqrt{3}}\]

    D)  3

    Correct Answer: C

    Solution :

    de-Broglie wavelength of an electron is given by \[\lambda =\frac{h}{mv}=\frac{h}{\sqrt{2mK}}\] or \[\lambda \propto \frac{1}{\sqrt{K}}\] \[\therefore \] \[\frac{\lambda }{\lambda }=\frac{1}{\sqrt{3K}}\frac{\sqrt{K}}{1}=\frac{1}{\sqrt{3}}\] or \[\lambda =\frac{\lambda }{\sqrt{3}}\] Hence, de-Broglie wavelength will change by factor\[\frac{1}{\sqrt{3}}.\]


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