CET Karnataka Medical CET - Karnataka Medical Solved Paper-2009

  • question_answer
    A ray of light is incident on a plane mirror at an angle of\[60{}^\circ \]. The angle of deviation produced by the mirror is

    A)  \[120{}^\circ ~\]

    B)  \[30{}^\circ \]

    C)  \[60{}^\circ ~\]

    D)  \[90{}^\circ \]

    Correct Answer: C

    Solution :

    Here, angle of incidence, \[i={{60}^{o}}\] \[\therefore \]Angle of deviation \[\delta ={{180}^{o}}-(i+r)\] \[={{180}^{o}}-2i\] \[(As\,i=r)\] \[={{180}^{o}}-2\times {{60}^{o}}={{60}^{o}}\]


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