A) both \[H_{2}^{+}\] and \[H_{2}^{-}\] are equally stable
B) Both \[H_{2}^{+}\] and \[H_{2}^{-}\] do not exist
C) \[H_{2}^{-}\] is more stable than \[H_{2}^{+}\]
D) \[H_{2}^{+}\] is more stable than \[H_{2}^{-}\]
Correct Answer: D
Solution :
\[H_{2}^{+}:\sigma {{s}^{1}},\overset{*}{\mathop{\sigma }}\,1{{s}^{0}}\] Bond order \[=\frac{1}{2}\] \[H_{2}^{-}:\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{1}}\] Bond order \[=\frac{2-1}{2}=\frac{1}{2}\] The bond order of \[H_{2}^{+}\] and \[H_{2}^{-}\] are same but \[H_{2}^{+}\] is more stable than \[H_{2}^{-}\]. It is due to the presence of one electron in the antibonding molecular orbital in \[H_{2}^{-}\].
You need to login to perform this action.
You will be redirected in
3 sec
