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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2009

  • question_answer
    For the reaction \[{{H}_{2}}O(l){{H}_{2}}O(g)\]at \[373K\]and 1 atm pressure

    A)  \[\Delta H=0\]         

    B)  \[\Delta E=0\]

    C)  \[\Delta H=T\Delta S\]

    D)  \[\Delta H=\Delta E\]

    Correct Answer: C

    Solution :

    \[\Delta G=\Delta H-T.\Delta S\] For the reaction, \[{{H}_{2}}O(l){{H}_{2}}O(g)\] \[\Delta G=0\]     (at equilibrium) \[\therefore \] \[\Delta H=T.\Delta S\]


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