A) Ethyl bromide + alcoholic \[KCN\]
B) Propyl bromide + alcoholic \[KCN\]
C) Propyl bromide + alcoholic \[AgCN\]
D) Ethyl bromide + alcoholic \[AgCN\]
Correct Answer: A
Solution :
When ethyl bromide reacts with alcoholic KCN, propane nitrile is obtained as main product. \[{{C}_{2}}{{H}_{5}}Br+Alc.\,\,KCN\xrightarrow{{}}\underset{propane\,nitrile}{\mathop{{{C}_{2}}{{H}_{5}}CN}}\,\]
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