CET Karnataka Medical CET - Karnataka Medical Solved Paper-2010

  • question_answer
    Magnetic field at the centre of a circular coil of radius R due to i flowing through it is B. The magnetic field at a point .along the axis at distance R from the centre is

    A)  \[\frac{B}{2}\]

    B)  \[\frac{B}{4}\]

    C)  \[\frac{B}{\sqrt{8}}\]

    D)  \[\sqrt{8}B\]

    Correct Answer: C

    Solution :

    The magnetic field at a point along the axis at distance R from the centre of a circular coil of radius R carrying current i is \[{{B}_{A}}=\frac{{{\mu }_{0}}2\pi i{{R}^{2}}}{4\pi {{({{R}^{2}}+{{R}^{2}})}^{3/2}}}\] \[=\frac{{{\mu }_{0}}i}{2\sqrt{8}R}\] \[=\frac{B}{\sqrt{8}}\]\[\left[ {{B}_{\text{centre}}}=B=\frac{{{\mu }_{0}}i}{2R} \right]\]


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