A) 100 %
B) 125 %
C) 225 %
D) 25 %
Correct Answer: B
Solution :
Kinetic energy of the body, \[K=\frac{{{p}^{2}}}{2m}\] Since, the mass remains constant \[\therefore \] \[K\propto {{p}^{2}}\] \[\frac{{{K}_{2}}}{{{K}_{1}}}=\frac{p_{2}^{2}}{p_{1}^{2}}={{\left[ \frac{150}{100} \right]}^{2}}=\frac{9}{4}\] \[100\left[ \frac{{{K}_{2}}}{{{K}_{1}}}-1 \right]=\left( \frac{9}{4}-1 \right)\times 100=125%\]
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