A) \[{{M}_{1}}\ne {{M}_{2}},but{{Q}_{1}}={{Q}_{2}}\]
B) \[{{M}_{1}}={{M}_{2}}\]
C) \[{{Q}_{1}}={{Q}_{2}}\]
D) \[{{L}_{1}}={{L}_{2}}\]
Correct Answer: B
Solution :
For sphere 1, in equilibrium \[{{T}_{1}}\cos {{\theta }_{1}}={{M}_{1}}g\]and\[{{T}_{1}}\sin {{\theta }_{1}}={{F}_{1}}\] \[\therefore \] \[{{\theta }_{1}}=\frac{{{F}_{1}}}{{{M}_{1}}g}\] Similarly for sphere \[2,\tan {{\theta }_{2}}=\frac{{{F}_{2}}}{{{M}_{2}}g}\]F is same on both the charges, \[\theta \]will be same only if their masses M are equal.You need to login to perform this action.
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