A) \[\frac{2k}{a}\]
B) \[\frac{a}{2k}\]
C) \[\frac{a}{k}\]
D) \[ak\]
Correct Answer: C
Solution :
For zero order reactions, \[[A]=-kt+{{[A]}_{0}}\] where, \[{{[A]}_{0}}\] = initial concentration \[=a\] [A] = remaining concentration \[=a-a=0\] On putting values of \[{{[A]}_{0}}\] and [A], we get \[t=\frac{a}{k}\]
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