A) \[p{{K}_{a}}-\log 2\]
B) \[p{{K}_{a}}\]
C) \[p{{K}_{a}}+2\]
D) \[p{{K}_{a}}+\log 2\]
Correct Answer: D
Solution :
Initially \[[C{{H}_{3}}COONa]=0.1mol\] \[[C{{H}_{2}}COOH]=0.1mol\] when \[0.1mol\,C{{H}_{3}}COONa\] is added. \[[C{{H}_{3}}COONa]=0.1+0.1=0.2mol\] \[pH=p{{K}_{a}}+\log \frac{[salt]}{[acid]}\] \[=p{{K}_{a}}+\log \frac{0.2}{0.1}\] \[=p{{K}_{a}}+\log 2\]
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