A) \[{{10}^{20}}\]
B) \[{{10}^{5}}\]
C) \[10\]
D) \[{{10}^{10}}\]
Correct Answer: A
Solution :
In a galvanic cell, \[\Delta {{G}^{o}}=-nF{{E}^{o}}\] ... (i) Relationship between \[\Delta {{G}^{o}}\] and equilibrium constant \[\Delta {{G}^{o}}=-2.303RT\,\log \,{{K}_{p}}\] ... (ii) From Eqs. (i) and (ii), we get \[-2.303RT\,\log \,{{K}_{p}}=-nF{{E}^{o}}\] \[\,\log \,{{K}_{p}}=\frac{nF{{E}^{o}}}{2.303RT}=\frac{n{{E}^{o}}}{\frac{2.303RT}{F}}\] \[=\frac{2\times 0.59}{0.059}=20\] \[{{K}_{p}}=AL(20)\] (AL= Antilog) \[{{K}_{p}}={{10}^{20}}\]
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