A) \[600{}^\circ C\]
B) \[327{}^\circ C\]
C) \[54{}^\circ C\]
D) \[300{}^\circ C\]
Correct Answer: D
Solution :
We know for perfect gas \[V\propto T\] Here, \[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\] ...(i) According to question, \[{{V}_{1}}=V\] then \[{{V}_{2}}=2V\]and \[{{T}_{1}}=300K\] \[\therefore \] \[\frac{1}{2}=\frac{300}{{{T}_{2}}}\] \[{{T}_{2}}=600K\] \[{{T}_{2}}={{327}^{o}}C\] So, \[\Delta t=327-27={{300}^{o}}C\]
You need to login to perform this action.
You will be redirected in
3 sec
