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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2011

  • question_answer
    A parallel beam of light of wavelength \[\text{6000}\overset{\text{o}}{\mathop{\text{A}}}\,\]gets diffracted by a single slit of width 0,3 mm. The angular position of the first minima of diffracted light is

    A)  \[2\times {{10}^{-3}}rad~\]

    B)  \[3\times {{10}^{-3}}rad\]

    C)  \[1.8\times {{10}^{-3}}rad~~~\]

    D)  \[6\times {{10}^{-3}}rad\]

    Correct Answer: A

    Solution :

    Given, \[\lambda =6000{\AA}=6000\times {{10}^{-10}}m\] and \[n=0.3mm=0.3\times {{10}^{-3}}m\] \[0.3\times {{10}^{-3}}\times \sin \theta =6000\times {{10}^{-10}}\] \[\sin \theta =2\times {{10}^{-3}}\]or\[\theta =2\times {{10}^{-3}}\text{rad}\]


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