block B. The force of friction between blocks A and B is \[\left( g\text{ }=\text{ }10m{{s}^{-2}} \right)\]
A) 100 N
B) 40 N
C) 50 N
D) Zero
Correct Answer: D
Solution :
Total mass of blocks A and 5=2+8=10 kg Friction between surface and combination of A and B \[F=\mu R\] \[=0.5\times 10\times 10=50N\] Here applied force on box B is 10 N that is less than 50 N. So the system will be in rest because of this there is no friction between blocks A and B.
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