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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2011

  • question_answer
    A current of\[\left( \frac{2}{\sqrt{3}} \right)A\], produces a deflection of\[60{}^\circ \]in a tangent galvanometer. The reduction factor is

    A)  \[\left( \frac{2}{\sqrt{3}} \right)A\]

    B)  \[\left( \frac{2}{3} \right)A\]

    C)  \[2A\]

    D)  \[\left( \frac{3}{2} \right)A\]

    Correct Answer: B

    Solution :

    For tangent galvanometer \[I=K\tan \theta \] \[K=\frac{I}{\tan \theta }\] \[K=\frac{2/\sqrt{3}}{\tan {{60}^{o}}}\] \[K=\frac{2}{3}A\]


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