A) \[2\]
B) \[5\]
C) \[3\]
D) \[1\]
Correct Answer: C
Solution :
Partition coefficient \[=\frac{Conc.\,\,of\,\,Ag\,in\,molten\,Zn}{Conc.\,of\,Ag\,in\,moltenPb}\] Mass of \[Ag\] in lead at equilibrium \[=1-x\] Mass of \[Ag\] in \[Zn\] at equilibrium \[=x\] \[300=\frac{x/10}{1-x/100}=\frac{10x}{1-x}\] \[10x=300(1-x)\] \[10x=300-300x\] \[310x=300\] \[x=\frac{300}{310}\] \[x=\frac{30}{31}\] Amount of silver in molten lead \[=1-x=1-\frac{30}{31}=\frac{31-30}{31}=\frac{1}{31}\] \[\therefore \] % of silver \[=\frac{1}{31}\times 100\approx 3%\]You need to login to perform this action.
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