A) \[287\times {{10}^{-3}}\]
B) \[143.5\times {{10}^{-3}}\]
C) \[143.5\times {{10}^{-2}}\]
D) \[287\times {{10}^{-2}}\]
Correct Answer: A
Solution :
The reagent is \[[Cr{{({{H}_{2}}O)}_{5}}Cl]C{{l}_{2}}\] No. of moles of \[C{{l}^{-}}\] ion present \[=\frac{2\times 100\times 0.01}{1000}\] \[=0.002\] \[\therefore \] Mass of \[AgCl=0.002\times 143.5\] \[=0.287\] \[=287\times {{10}^{-3}}g\]
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