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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2012

  • question_answer
    The radius of \[_{29}C{{u}^{64}}\] nucleus in Fermi is (given \[{{R}_{0}}=1.2\times {{10}^{-15}}m\])

    A)  \[4.8\]   

    B)  \[1.2\]   

    C)  \[7.7\]  

    D)  \[9.6\]

    Correct Answer: A

    Solution :

    : Nuclear radius \[R={{R}_{0}}{{A}^{1/3}}\] where \[{{R}_{0}}\]is a constant and A is the mass number \[{{R}_{Cu}}=(1.2\times {{10}^{-15}}m)\,{{(64)}^{1/3}}\] \[=(1.2\times {{10}^{-15}}m)\,{{({{4}^{3}})}^{1/3}}\] \[=4.8\times {{10}^{-15}}m=4.8fm\]    ( \[\because \] \[1fm={{10}^{-15}}m\])


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