A) \[s{{p}^{3}}-s\]and \[s{{p}^{3}}-s{{p}^{3}}\]
B) \[s{{p}^{2}}-s\]and \[s{{p}^{2}}-s{{p}^{2}}\]
C) \[sp-s\]and \[sp-sp\]
D) \[p-s\]and \[p-p\]
Correct Answer: A
Solution :
\[s{{p}^{3}}-s\]and \[s{{p}^{3}}-s{{p}^{3}}\]
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