A) \[Z-11,\,A-16\]
B) \[Z-5,\text{ }A-13\]
C) \[Z-5,\text{ }A-16\]
D) \[Z-8,\text{ }A-13\]
Correct Answer: C
Solution :
: Emission of a-particle decreases the atomic number and mass number by 2 and 4 respectively. Emission of \[\beta \]-particle increases the atomic number by 1 while the mass number remains unchanged. Emission of \[\gamma \]-particle both the atomic number and the mass number remain unchanged. \[\therefore \]After the emission of four a-particles, three \[\beta \]-particles and eight y photons, Decrease in atomic number \[=4\times 2-3\times 1=5\] Decrease in mass number \[=4\times 4-0=16\] Thus, the atomic number and mass number of resulting final nucleus are \[Z-5\] and \[A-16\] respectively. \[\therefore \] The resulting final nucleus is \[_{Z-5}{{Y}^{A-16}}\].
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