A) \[5m\]
B) \[10m\]
C) \[7.5m\]
D) \[20m\]
Correct Answer: A
Solution :
: Time taken by the ball to reach highest point is \[t=1s\] As the person throws the second ball, when the velocity of the first ball becomes zero, i.e., \[\upsilon =0\] or when the first ball reach the highest point. Using, \[\upsilon =u+at\] Here, \[\upsilon =0,a=-g,t=1s\] \[\therefore \] \[0=u-(10)(1)\] \[u=10m/s\] Using \[{{\upsilon }^{2}}-{{u}^{2}}=2ah,\]we get \[{{(0)}^{2}}-{{(10)}^{2}}=2(-10)(h)\] \[h=\frac{{{(10)}^{2}}}{20}=5m\]
You need to login to perform this action.
You will be redirected in
3 sec
