CET Karnataka Medical CET - Karnataka Medical Solved Paper-2012

  • question_answer
    A current of 2 A is passing through a metal wire of cross sectional area \[2\times {{10}^{-6}}{{m}^{2}}\]. If the number density of free electrons in the wire is \[5\times {{10}^{26}}{{m}^{-3}}\], the drift speed of electrons is (given \[e=1.6\times {{10}^{-19}}C\])

    A)  \[\frac{1}{16}m{{s}^{-1}}\]

    B)  \[\frac{1}{40}m{{s}^{-1}}\]

    C)  \[\frac{1}{80}m{{s}^{-1}}\]    

    D)  \[\frac{1}{32}m{{s}^{-1}}\]

    Correct Answer: C

    Solution :

    : Here, Current, \[I=2A\] Area of cross-section, \[A=2\times {{10}^{-6}}{{m}^{2}}\] Number density of free electrons, \[n=5\times {{10}^{26}}{{m}^{-3}}\] The drift speed of electrons is \[{{\upsilon }_{d}}=\frac{I}{nAe}\] \[=\frac{2A}{(5\times {{10}^{26}}{{m}^{-3}})(2\times {{10}^{-6}}{{m}^{2}})(1.6\times {{10}^{-19}}C)}\] \[=\frac{1}{80}m{{s}^{-1}}\]


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