A) \[1:4\]
B) \[1:2\]
C) \[1:8\]
D) \[1:16\]
Correct Answer: D
Solution :
: According to Rayleigh scattering \[I\propto {{(\upsilon )}^{4}}\] \[\therefore \] \[\frac{{{I}_{1}}}{{{I}_{2}}}={{\left( \frac{{{\upsilon }_{1}}}{{{\upsilon }_{2}}} \right)}^{4}}={{\left( \frac{1}{2} \right)}^{4}}=\frac{1}{16}\]
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